JavaWeb项目实现文件上传动态显示进度
引用:
很久没有更新博客了,这段时间实在的忙的不可开交,项目马上就要上线了,要修补的东西太多了。当我在学习JavaWeb文件上传的时候,我就一直有一个疑问,网站上那些博客的图片是怎么上传的,因为当提交了表单之后网页就跳转了。后来我学习到了Ajax,我知道了浏览器可以异步的发送响应,这时我又有新的疑问,那就是在我上传一些文件的时候,那些网站的上传进度是怎么做到的,因为servlet直到上传完成之后才完成响应。
最近我们的项目中有一个地方中需要用到一个功能,当用户点击一个处理按钮时,前台会实时的显示后台处理动态,由于servlet一次只能接受一个请求,而且在servlet的生命周期结束时才会把响应数据发送到前台(这一点大家可以做个这样的测试:
1 response.getWriter().print("hello");
2 Thread.sleep(10000);
3 response.getWriter().print("world");
,你们会发现前台在等待了约10s后收到了"helloworld")。所以我想到了一个方法:使用单例保存实时信息。具体的实现方法就是,当用户点击了处理按钮时,在后台开启一个线程进行处理,并且每进行到一步,就向单例中写入当前状态信息。然后编写一个servlet,用于返回单例中的信息,前台循环发送请求,这样就能实现实时显示进度的效果。
好了,啰嗦了这么多,下面进入正题,如何实现上传文件动态显示进度,其实思想和上面的功能是一致的,我将这个功能分为三个点:
- 单例:用于保存进度信息;
- 上传servlet:用于上传文件并实时写入进度;
- 进度servlet:用于读取实时进度信息;
上代码,前台:
1 2 3 4 518 19 <script type="text/javascript" src="scripts/jquery-1.9.1.min.js"></script> 20 <script type="text/javascript"> 21 (function () { 22 var form = document.getElementById("dataForm"); 23 var progress = document.getElementById("progress"); 24 25 $("#submit").click(function(event) { 26 //阻止默认事件 27 event.preventDefault(); 28 //循环查看状态 29 var t = setInterval(function(){ 30 $.ajax({ 31 url: 'ProgressServlet', 32 type: 'POST', 33 dataType: 'text', 34 data: { 35 filename: fileInput.files[0].name, 36 }, 37 success: function (responseText) { 38 var data = JSON.parse(responseText); 39 //前台更新进度 40 progress.innerText = parseInt((data.progress / data.size) * 100); 41 }, 42 error: function(){ 43 console.log("error"); 44 } 45 }); 46 }, 500); 47 //上传文件 48 $.ajax({ 49 url: 'UploadServlet', 50 type: 'POST', 51 dataType: 'text', 52 data: new FormData(form), 53 processData: false, 54 contentType: false, 55 success: function (responseText) { 56 //上传完成,清除循环事件 57 clearInterval(t); 58 //将进度更新至100% 59 progress.innerText = 100; 60 }, 61 error: function(){ 62 console.log("error"); 63 } 64 }); 65 return false; 66 }); 67 })(); 68 </script> 69 70Insert title here 6 11 12 13File upload demo
14
后台,单例:
1 import java.util.Hashtable;
2
3 public class ProgressSingleton {
4 //为了防止多用户并发,使用线程安全的Hashtable
5 private static Hashtable
上传servlet:
1 import java.io.File;
2 import java.io.FileOutputStream;
3 import java.io.IOException;
4 import java.io.InputStream;
5 import java.util.List;
6
7 import javax.servlet.ServletException;
8 import javax.servlet.annotation.WebServlet;
9 import javax.servlet.http.HttpServlet;
10 import javax.servlet.http.HttpServletRequest;
11 import javax.servlet.http.HttpServletResponse;
12
13 import org.apache.tomcat.util.http.fileupload.FileItem;
14 import org.apache.tomcat.util.http.fileupload.FileUploadException;
15 import org.apache.tomcat.util.http.fileupload.disk.DiskFileItemFactory;
16 import org.apache.tomcat.util.http.fileupload.servlet.ServletFileUpload;
17 import org.apache.tomcat.util.http.fileupload.servlet.ServletRequestContext;
18
19 import singleton.ProgressSingleton;
20
21 @WebServlet("/UploadServlet")
22 public class UploadServlet extends HttpServlet {
23 private static final long serialVersionUID = 1L;
24
25 public UploadServlet() {
26 }
27
28 protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
29
30 DiskFileItemFactory factory = new DiskFileItemFactory();
31 factory.setSizeThreshold(4*1024);
32
33 ServletFileUpload upload = new ServletFileUpload(factory);
34
35 List fileItems;
36 try {
37 fileItems = upload.parseRequest(new ServletRequestContext(request));
38 //获取文件域
39 FileItem fileItem = fileItems.get(0);
40 //使用sessionid + 文件名生成文件号
41 String id = request.getSession().getId() + fileItem.getName();
42 //向单例哈希表写入文件长度和初始进度
43 ProgressSingleton.put(id + "Size", fileItem.getSize());
44 //文件进度长度
45 long progress = 0;
46 //用流的方式读取文件,以便可以实时的获取进度
47 InputStream in = fileItem.getInputStream();
48 File file = new File("D:/test");
49 file.createNewFile();
50 FileOutputStream out = new FileOutputStream(file);
51 byte[] buffer = new byte[1024];
52 int readNumber = 0;
53 while((readNumber = in.read(buffer)) != -1){
54 //每读取一次,更新一次进度大小
55 progress = progress + readNumber;
56 //向单例哈希表写入进度
57 ProgressSingleton.put(id + "Progress", progress);
58 out.write(buffer);
59 }
60 //当文件上传完成之后,从单例中移除此次上传的状态信息
61 ProgressSingleton.remove(id + "Size");
62 ProgressSingleton.remove(id + "Progress");
63 in.close();
64 out.close();
65 } catch (FileUploadException e) {
66 e.printStackTrace();
67 }
68
69 response.getWriter().print("done");
70 }
71
72 protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
73 doGet(request, response);
74 }
75
76 }
进度servlet:
1 import java.io.IOException;
2
3 import javax.servlet.ServletException;
4 import javax.servlet.annotation.WebServlet;
5 import javax.servlet.http.HttpServlet;
6 import javax.servlet.http.HttpServletRequest;
7 import javax.servlet.http.HttpServletResponse;
8
9 import net.sf.json.JSONObject;
10 import singleton.ProgressSingleton;
11
12 @WebServlet("/ProgressServlet")
13 public class ProgressServlet extends HttpServlet {
14 private static final long serialVersionUID = 1L;
15
16 public ProgressServlet() {
17 super();
18 // TODO Auto-generated constructor stub
19 }
20
21 protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
22
23 String id = request.getSession().getId();
24 String filename = request.getParameter("filename");
25 //使用sessionid + 文件名生成文件号,与上传的文件保持一致
26 id = id + filename;
27 Object size = ProgressSingleton.get(id + "Size");
28 size = size == null ? 100 : size;
29 Object progress = ProgressSingleton.get(id + "Progress");
30 progress = progress == null ? 0 : progress;
31 JSONObject json = new JSONObject();
32 json.put("size", size);
33 json.put("progress", progress);
34 response.getWriter().print(json.toString());
35 }
36
37 protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
38 doGet(request, response);
39 }
40
41 }
效果图:https://stackoverflow.com/questions/42164380/asp-net-core-file-upload-progress-session
引用网址:
ASP.Net Core File Upload Progress Session
Ask Question Asked 5 years ago Active 5 years ago Viewed 7k timesI'm writing a file upload in ASP.Net Core and I'm trying to update a progress bar but when the Progress action is called from javascript, the session value isn't updated properly.
The progress is saved in the user Session using:
public static void StoreInt(ISession session, string key, int value)
{
session.SetInt32(key, value);
}
The upload:
$.ajax(
{
url: "/Upload",
data: formData,
processData: false,
contentType: false,
type: "POST",
success: function (data) {
clearInterval(intervalId);
$("#progress").hide();
$("#upload-status").show();
}
}
);
Getting the progress value:
intervalId = setInterval(
function () {
$.post(
"/Upload/Progress",
function (progress) {
$(".progress-bar").css("width", progress + "%").attr("aria-valuenow", progress);
$(".progress-bar").html(progress + "%");
}
);
},
1000
);
Upload Action:
[HttpPost]
public async Task Index(IList files)
{
SetProgress(HttpContext.Session, 0);
[...]
foreach (IFormFile file in files)
{
[...]
int progress = (int)((float)totalReadBytes / (float)totalBytes * 100.0);
SetProgress(HttpContext.Session, progress);
// GetProgress(HttpContext.Session) returns the correct value
}
return Content("success");
}
Progress Action:
[HttpPost]
public ActionResult Progress()
{
int progress = GetProgress(HttpContext.Session);
// GetProgress doesn't return the correct value: 0 when uploading the first file, a random value (0-100) when uploading any other file
return Content(progress.ToString());
}
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asked Feb 10, 2017 at 16:38
xmlHttpRequestthat creates a live connection, But it is asp.net not mvc. Do you want that? – Farzin Kanzi Feb 13, 2017 at 15:20