Java解析XML格式的字符串
1 解析Xml
1.1 添加项目依赖
dom4j dom4j 1.6.1
1.2 返回的Xml使用字符串换行
String returnMsg = "<?xml version=\"1.0\" encoding=\"gb2312\"?>" + "" + " ";" + "
" + "001 " + "张三 " + "22 " + "" + "
" + "002 " + "李四 " + "33 " + "
测试代码
@Test
public void test1() {
String returnMsg = "<?xml version=\"1.0\" encoding=\"gb2312\"?>" +
"" +
"" +
"001 " +
"张三 " +
"22 " +
"
" +
"" +
"002 " +
"李四 " +
"33 " +
"
" +
" ";
try {
Document doc = DocumentHelper.parseText(returnMsg);
Element roots = doc.getRootElement();
// System.out.println("根节点 = [" + roots.getName() + "]");
// System.out.println("内容:" + roots.getText());
Iterator elements = roots.elementIterator();
while (elements.hasNext()) {
Element child = (Element) elements.next();
//System.out.println("节点名称 = [" + child.getName() + "]"+"节点内容:"+child.getText());
List subElements = child.elements();
List
测试结果
1.3 返回的Xml没有换行
String strXML = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>"; 7474741 不服?咋滴 88 {\"jobId\":\"666888\",\"requestId\":\"639D1D03-1557-4AD7-9AD7-691F02834516\",\"state\":\"Success\"}
测试代码
@Test
public void test2() {
String strXML = "<?xml version=\"1.0\" encoding=\"UTF-8\"?> 7474741 不服?咋滴 88 {\"jobId\":\"666888\",\"requestId\":\"639D1D03-1557-4AD7-9AD7-691F02834516\",\"state\":\"Success\"} ";
try {
Document doc = DocumentHelper.parseText(strXML);
// 指向根节点
Element root = doc.getRootElement();
Iterator it = root.elementIterator();
while (it.hasNext()) {
// 一个Item节点
Element element = (Element) it.next();
System.out.println(element.getName() + " : " + element.getTextTrim());
}
} catch (DocumentException e) {
e.printStackTrace();
}
}
测试结果