ShortestPathOfDijkstra
package graph.dijkstra;
import java.util.Arrays;
/**
* description
* 狄克斯特拉算法的时间复杂度O(n^2)
* https://blog.csdn.net/shui2104/article/details/107053966
* https://www.bbsmax.com/A/qVde9lOrdP/
*
* @author liekkas 2021/08/22 16:14
*/
public class ShortestPathOfDijkstra {
private static final int MAX = 10000;
/**
* 接受一个有向图的权重矩阵,和一个起点编号start(从0编号,顶点存在数组中)
*
* @param graph graph
* @param startPointIndex startPointIndex
* @return 返回一个int[] 数组,表示从start到它的最短路径长度
*/
public static int[] dijsktra(int[][] graph, int startPointIndex) {
int length = graph.length;
//标记当前该顶点的最短路径是否已经求出,true表示已经求出
boolean[] visited = new boolean[length];
//start点的最短距离已经求出
for (int i = 0; i < graph.length; i++) {//初始化s集合,只有起始点
if (i == startPointIndex) {
visited[i] = true;
} else {
visited[i] = false;
}
}
//存放从start到各个点的最短距离
int[] shortDistance = new int[length];
for (int i = 0; i < graph.length; i++) {//初始化,起始点到其他点的距离。
shortDistance[i] = graph[startPointIndex][i];
}
//start到他本身的距离最短为0
shortDistance[startPointIndex] = 0;
//存放从start点到各点的最短路径的字符串表示
String[] path = new String[length];
for (int i = 0; i < length; i++) {
path[i] = startPointIndex + "->" + i;
}
for (int count = 1; count < length; count++) {
int k = -1;
int dmin = MAX;
for (int i = 0; i < length; i++) {
if (!visited[i] && shortDistance[i] < dmin) {
dmin = shortDistance[i];
k = i;
}
}
//选出一个距离start最近的未标记的顶点 将新选出的顶点标记为以求出最短路径,且到start的最短路径为dmin。
shortDistance[k] = dmin;
visited[k] = true;
//以k为中间点,修正从start到未访问各点的距离
for (int i = 0; i < length; i++) {
if (!visited[i] && shortDistance[k] + graph[k][i] < shortDistance[i]) {
shortDistance[i] = shortDistance[k] + graph[k][i];
path[i] = path[k] + "->" + i;
}
}
}
for (int i = 0; i < length; i++) {
System.out.println("从" + startPointIndex + "出发到" + i + "的最短路径为:" + path[i] + "=" + shortDistance[i]);
}
return shortDistance;
}
public static void main(String[] args) {
int[][] graph = {
{0, 4, 6, 6, MAX, MAX, MAX},
{MAX, 0, 1, MAX, 7, MAX, MAX},
{MAX, MAX, 0, MAX, 6, 4, MAX},
{MAX, MAX, 2, 0, MAX, 5, MAX},
{MAX, MAX, MAX, MAX, 0, MAX, 6},
{MAX, MAX, MAX, MAX, 1, 0, 8},
{MAX, MAX, MAX, MAX, MAX, MAX, MAX}};
int start = 0;
int[] dijsktra = dijsktra(graph, start);
System.out.println(Arrays.toString(dijsktra));
}
}
ShortestPathOfFloyd
package graph.floyd;
/**
* description floyd最短路径
* 时间复杂度O(V*E) 空间复杂度O(V^2)
* https://blog.csdn.net/qq_34842671/article/details/90637502
*
* @author liekkas 2021/08/22 13:35
*/
public class ShortestPathOfFloyd {
private final static int VERTEX = 7;
private final static int[][] MATRIX = new int[VERTEX][VERTEX];
private final static int[][] PATH = new int[MATRIX.length][MATRIX.length];
private final static int MAX_VALUE = 100000;
/**
* 初始化邻接矩阵
*/
static void initMatrix() {
for (int i = 0; i < VERTEX; i++) {
for (int j = 0; j < VERTEX; j++) {
MATRIX[i][j] = MAX_VALUE;
}
}
}
/**
* 初始化边
*/
static void initEdge() {
MATRIX[0][1] = 6;
MATRIX[0][3] = 2;
MATRIX[1][2] = 5;
MATRIX[1][5] = 3;
MATRIX[3][4] = 5;
MATRIX[3][1] = 7;
MATRIX[4][6] = 1;
MATRIX[5][4] = 2;
MATRIX[5][2] = 3;
}
public static void main(String[] args) {
initMatrix();
initEdge();
//调用算法计算最短路径
floyd(MATRIX);
}
@SuppressWarnings("all")
private static void floyd(int[][] matrix) {
for (int i = 0; i < matrix.length; i++) {
for (int j = 0; j < matrix.length; j++) {
PATH[i][j] = -1;
}
}
for (int m = 0; m < matrix.length; m++) {
for (int i = 0; i < matrix.length; i++) {
for (int j = 0; j < matrix.length; j++) {
if (matrix[i][m] + matrix[m][j] < matrix[i][j]) {
matrix[i][j] = matrix[i][m] + matrix[m][j];
//记录经由哪个点到达
PATH[i][j] = m;
}
}
}
print(MATRIX);
}
/* for (int i = 0; i < matrix.length; i++) {
for (int j = 0; j < matrix.length; j++) {
if (i != j) {
if (matrix[i][j] == MAX_VALUE) {
System.out.println(i + "到" + j + "不可达");
} else {
System.out.print(i + "到" + j + "的最短路径长度是:" + matrix[i][j]);
System.out.print("最短路径为:" + i + "->");
findPath(i, j);
System.out.println(j);
}
}
}
}*/
int i = 0, j = 5;
if (matrix[i][j] == MAX_VALUE) {
System.out.println(i + "到" + j + "不可达");
} else {
System.out.print(i + "到" + j + "的最短路径长度是:" + matrix[i][j]);
System.out.print("最短路径为:" + i + "->");
findPath(i, j);
System.out.println(j);
}
}
private static void findPath(int i, int j) {
int m = PATH[i][j];
if (m == -1) {
return;
}
findPath(i, m);
System.out.print(m + "->");
findPath(m, j);
}
static void print(int[][] a) {
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a[i].length; j++) {
System.out.printf("%-10d", a[i][j]);
if (j != a[i].length - 1) {
System.out.print(",");
}
}
System.out.println();
}
}
}