python 穷举

import random

def getpwd(ab,num):
    if num==1:
        for x in ab:
            yield x
    else:
        for x in ab:
            for y in getpwd(ab,num-1):
                yield x+y

from itertools import product
from time import sleep
from tqdm import tqdm

#密码生成器
def psgen(x=1):
   iter = ['1234567890e']  #ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890abcdefghijklmnopqrstuvwxyz
   for r in iter:
       for repeat in range(x,x+1):
           for ps in product(r,repeat=repeat):
                yield ''.join(ps)
                print(ps)
sum=0
s="123123e"  #要破解的口令
print("wait...")
for ps in tqdm(psgen(len(s))): #多少位
  sum+=1
  if(ps==s):
    print("破解成功！密码为："+ps)
    break
print("计算了"+str(sum)+"次")
print("完成！")