ajax练习
html代码
"text" id="userid">"show">
php代码
<?php $userId = isset($_GET['user_id']) ? $_GET['user_id'] : null; $userInfo = [ ['user_id'=>1, 'username'=>'苍老师', 'gender'=>'女', 'age'=>26], ['user_id'=>2, 'username'=>'波老师', 'gender'=>'女', 'age'=>23], ['user_id'=>3, 'username'=>'黑老师', 'gender'=>'男', 'age'=>33], ]; $res = ''; foreach ($userInfo as $user) { if ($user['user_id'] === intval($userId)) { $res .= $user['user_id'].'---'.$user['username'].'---'.$user['gender'].'---'.$user['age']; } } echo empty($res) ? '没有找到该用户名' : $res; exit;