ajax练习


html代码

    
"text" id="userid">
"show">

php代码

<?php
$userId = isset($_GET['user_id']) ? $_GET['user_id'] : null;

$userInfo = [
    ['user_id'=>1, 'username'=>'苍老师', 'gender'=>'', 'age'=>26],
    ['user_id'=>2, 'username'=>'波老师', 'gender'=>'', 'age'=>23],
    ['user_id'=>3, 'username'=>'黑老师', 'gender'=>'', 'age'=>33],
];

$res = '';
foreach ($userInfo as $user) {
    if ($user['user_id'] === intval($userId)) {
        $res .= $user['user_id'].'---'.$user['username'].'---'.$user['gender'].'---'.$user['age'];
    }
}

echo empty($res) ? '没有找到该用户名' : $res;
exit;