C++ 指针 * 和 引用 &

指针

先看一个简单的例子：

#include 
using namespace std;

int main() {
    // your code goes here
    int num = 123;
    int* p = #
    cout<<"p:"<endl;
    cout<<"*p:"<<*p<<endl;
    cout<<"num:"<endl;
    cout<<"&num:"<<&num<<endl;
    return 0;
}

运行结果：

p:0x7ffc2861549c
*p:123
num:123
&num:0x7ffc2861549c

p是指向num地址的指针，所以p的值为num的地址。可以给*p赋值，此时num值也会发生相应的变化，但是不会因此而改变p所指向的地址。

#include 
using namespace std;

int main() {
    int num = 123;
    int* p = # // 这里&为取址
    cout<<"*p = "<<*p<<endl;
    cout<<"p = "<endl;
    
    *p = NULL;
    cout<<"*p = "<<*p<<endl;
    cout<<"p = "<endl;
    cout<<"num = "<endl;
}

*p = 123
p = 0x7ffccb7a153c
*p = 0
p = 0x7ffccb7a153c
num = 0

引用

C++引用

类型标识符 &引用名=目标变量名

#include 
using namespace std;

int main() {
    int num1 = 1, num2 = 2;
    int &ref1 = num1, &ref2 = num2; ///引用必须要初始化
    cout<<"num1 = "<",num2 = "<endl;
    cout<<"ref1 = "<",ref2 = "<endl;
    ///修改引用的值将改变其所绑定的变量的值
    ref1 = -1;
    cout<<"num1 = "<",ref1 = "<endl;
    
    ///将引用b赋值给引用a将改变引用a所绑定的变量的值，
    ///引用一但初始化(绑定)，将始终绑定到同一个特定对象上，无法绑定到另一个对象上
    ref1 = ref2;
    cout<<"num1 = "<",ref1 = "<endl;
    return 0;
}

num1 = 1,num2 = 2
ref1 = 1,ref2 = 2
num1 = -1,ref1 = -1
num1 = 2,ref1 = 2

指向指针的指针

#include 
using namespace std;

int main() {
    int val = 1;
    int *p1 = &val;
    int **p2 = &p1;///**声明一个指向指针的指针
    cout<<"val = "<endl;
    cout<<"p1 = "<", *p1 = "<<*p1<<endl;
    cout<<"p2 = "<", *p2 = "<<*p2<<",**p2 = "<<**p2<<endl;
    return 0;
}

val = 1
p1 = 0x7ffe520c3d34, *p1 = 1
p2 = 0x7ffe520c3d38, *p2 = 0x7ffe520c3d34,**p2 = 1

指针与数组

#include 
using namespace std;

int main() {
    int arr[5][5];
    arr[2][1] = 666;
    cout<<*(*(arr + 2) + 1)<<endl;
    return 0;
}

#include 
using namespace std;

int main() {
    int arr[100];
    for (int i = 0; i < 100; i++)
        arr[i] = i;
    int *p = arr;  //等价于int *p = &arr[0];
    //数组的变量名就是一个指针
    cout<<"p = "<",*p = "<<*p< 0
    
    int t = 100;
    while (t--)
        ///可以直接对指针进行加减运算，就和迭代器一样
        cout<<*(p++)<指针可以做差：
    int *p2 = &arr[10], *p3 = &arr[20];
    cout<<"p2 - p3 = "<<(p2 - p3)<还可以比比较大小：
    cout<<(p2 < p3 ? p3 - p2 : p2 - p3)<return 0;
}