剑指 Offer 24. 反转链表

题目

剑指 Offer 24. 反转链表

代码

class Solution {
public:
    ListNode* reverseList(ListNode* head) {
        ListNode *pre = nullptr;
        auto cur = head;
        while(cur)
        {
            auto next = cur->next;
            cur->next = pre;
            pre = cur;
            cur = next;
        }
        return pre;
    }
};