Spring的transaction-manager的用法

2）transaction-manager：

例 2.2.2

注意配置文件头加了两条：spring-tx-3.0.xsd和xmlns:tx

<?xml version="1.0" encoding="UTF-8"?>
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:aop="http://www.springframework.org/schema/aop"
    xmlns:p="http://www.springframework.org/schema/p"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context-3.0.xsd
        http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd"
       >
 
            base-package="com" />
            base-package="service" />
            class="org.springframework.web.servlet.view.UrlBasedViewResolver">
                    value="org.springframework.web.servlet.view.JstlView" />
       
       
   
   
   
   
       
           
       
   
   
   
       
           
       
   
    
   
   
       
                
   
   
                               value="com.mysql.jdbc.Driver">
                               value="jdbc:mysql://localhost:3306/test">
                               value="root">
                               value="1234">
   
   
       
   
      class="org.springframework.jdbc.datasource.DataSourceTransactionManager">
       
   


package service;
import java.sql.Types;
import javax.annotation.Resource;
import org.springframework.jdbc.core.JdbcTemplate;
import com.NiutDAO;
import service.interfac.ILoginService;

public class LoginServiceImpl implements ILoginService {
    @Resource
    private JdbcTemplate jt;
    
    NiutDAO niutDAO;
    public void setNiutDAO(NiutDAO niutDAO) {
        this.niutDAO = niutDAO;
    }
    public void login() {
        updateRegister(15,1);
        System.out.println("successfully update 1");
        updateRegisterWrong(19,2);
        System.out.println("successfully update 2");

    }    
    public void updateRegister(int age,int id) {
        String sql = "UPDATE register SET age=? WHERE id=?";
        Object params[] = new Object[] { new Integer(age),
                 new Integer(id) };
        int type[] = new int[] { Types.INTEGER , Types.INTEGER };
        jt.update(sql, params, type);
    }
    public void updateRegisterWrong(int age,int id) {
        String sql = "UPDATE register SET age=? WWWWWWW id=?";
        Object params[] = new Object[] { new Integer(age),
                new Integer(id) };
        int type[] = new int[] { Types.INTEGER , Types.INTEGER };
        jt.update(sql, params, type);
    }
}

即使updateRegister(15,1);成功执行，但数据库中结果并没有被更新，因为updateRegisterWrong(19,2);的错误致使updateRegister(15,1);的结果发生了回滚。

输出结果：
successfully update 1
严重: Servlet.service() for servlet spring threw exception
java.sql.SQLException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WWWWWWW id=2' at line 1
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:2921)
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1570)

更多内容请见原文，文章转载自：https://blog.csdn.net/qq_44591615/article/details/109206425