Pandas嵌套词典解析或取值
# tribe列只保留name 值 df['tribe']=df['tribe'].apply(lambda x:eval(x)['name']) # tribe 列全部项目展开 df=df['content'].apply(pd.Series)
# tribe列只保留name 值 df['tribe']=df['tribe'].apply(lambda x:eval(x)['name']) # tribe 列全部项目展开 df=df['content'].apply(pd.Series)