C语言程序设计-笔记8-结构

C语言程序设计-笔记8-结构

例9-1  输出平均分最高的学生信息。根据学生的基本信息包括学号、姓名、三门课程成绩以及个人平均成绩。输入n个学生的成绩信息，计算并输出平均分最高的学生信息。

#include

struct student{

     int num;

     char name[10];

     int computer,english,math;

     double average;

};

int main(void)

     int i,n;

     struct student max,stu;

     printf("Input n:");

     scanf("%d",&n);

     printf("Input the student's number,name and course scores\n");

     for(i=1;i<=n;i++)

     {

         printf("No.%d:",i);

         scanf("%d%s%d%d%d",&stu.num,stu.name,&stu.math,&stu.english,

&stu.computer);

         stu.average=(stu.math+stu.english+stu.computer)/3.0;

         if(i==1)

         {

              max=stu;

         }

         else if(max.average

         {

              max=stu;

         }

     }

     printf("num:%d,name:%s,average:%.2f\n",max.num,max.name,max.average);

     return 0;

例9-2  学生成绩排序。输入n（n〈50）个学生的成绩信息，按照学生的个人平均成绩从高到低输出他们的信息。

#include

struct student{

     int num;

     char name[10];

     int computer,english,math;

     double average;

     };

int main(void)   

     int i,index,j,n;

     struct student students[50],temp;

     printf("Input n:");

     scanf("%d",&n);

     for(i=0;i

     {

         printf("Input the info of No.%d:\n",i+1);

         printf("number:");

         scanf("%d",&students[i].num);

         printf("name:");

         scanf("%s",students[i].name);

         printf("math score:");

         scanf("%d",&students[i].math);

         printf("english score:");

         scanf("%d",&students[i].english);

         printf("computer score:");

         scanf("%d",&students[i].computer);

         students[i].average=(students[i].math+students[i].english+

                                 students[i].computer)/3.0;

     }

     for(i=0;i

     {

         index=i;

         for(j=i+1;j

         {

              if(students[j].average>students[index].average)

              {

                   index=j;

              }

         }       

              temp=students[index];

              students[index]=students[i];

              students[i]=temp;

     }

     printf("num\t name\t average\n");

     for(i=0;i

     {

         printf("%d \t%s \t%.2f\n",students[i].num,students[i].name,

                   students[i].average);

     }

     return 0;

例9-3  修改学生成绩。输入n(n<50)个学生的成绩信息，再输入一个学生的学号、课程以及成绩，在自定义函数中修改该学生指定课程的成绩。

#include

struct student{

     int num;

     char name[10];

     int computer,english,math;

     double average;

};

int update_score(struct student *p,int n,int num,int course,int score);

int main(void)

     int course,i,n,num,pos,score;

     struct student students[50];

     printf("Input n:");

     scanf("%d",&n);

     for(i=0;i

     {

         printf("Input the info of No.%d:\n",i+1);

         printf("number:");

         scanf("%d",&students[i].num);

         printf("name:");

         scanf("%s",students[i].name);

         printf("math score:");

         scanf("%d",&students[i].math);

         printf("english score:");

         scanf("%d",&students[i].english);

         printf("computer score:");

         scanf("%d",&students[i].computer);

     }

     printf("Input the number of the students to be updated:");

     scanf("%d",&num);

     printf("Choice the course:1.math 2.english 3.computer:");

     scanf("%d",&course);

     printf("Input the new score:");

     scanf("%d",&score);

     pos=update_score(students,n,num,course,score);

     if(pos==-1)

     {

         printf("Not found!\n");

     }

     else

     {

         printf("After update:\n");

         printf("num\t math\t english\t computer\n");

         printf("%d\t %d\t %d\t %d\n",students[pos].num,students[pos].math,

                   students[pos].english,students[pos].computer);

     }

     return 0;

int update_score(struct student *p,int n,int num,int course,int score)

     int i,pos;

     for(i=0;i

     {

         if(p->num==num)

         {

              break;

         }

     }

     if(i

     {

         switch(course)

         {

              case 1:p->math=score;break;

              case 2:p->english=score;break;

              case 3:p->computer;break;

         }

         pos=i;

     }

     else

     {

         pos=-1;

     }

     return pos;

参考资料

C语言程序设计/何钦铭，颜晖主编.---4版.---北京：高等教育出版社，2020.9