public int lengthOfLongestSubstring(String s) {
// 开一个hashmap来维护情况,进行一个N*N的搜索
Map map;
int len = s.length();
if(len == 0) return 0;
int[] board = new int[len];
int ans = 1;
for(int i = 0; i < s.length(); i++) {
Character chi = s.charAt(i);
map = new HashMap<>();
map.put(chi, true);
board[i] = 1;
for(int j = i+1; j < len; j++) {
Character chj = s.charAt(j);
if(!map.containsKey(chj) || !map.get(chj)) {
map.put(chj, true);
board[i] = board[i] + 1;
ans = Math.max(ans, board[i]);
}
else break;
}
map.put(chi, false);
}
return ans;
}